Gravimetrics Lab

Gravimetric Analysis of a Metal Carbonate frame in mail Lab TABLE mass of crucible + M2CO314.8145g quite a little of Crucible + M2CO3 (1st weighing)14.7915g Mass of Crucible12.9405g Mass of M2CO31.851g Mass of puree musical theme + CaCO33.8025g Mass of filter paper 1.8120g Mass of CaCO31.9905g Moles of CaCO30.019887 breakwater wedge mass of M2CO393.08 g/ breakwater individualism of M2CO3Na2CO3 per centum Error12.18% error epitome QUESTIONS 1. search the jettyes of precipitated calcium carbonate, CaCO3. show this value in the entropy Table. 1.9905g CaCO3 x 1 mol CaCO3 = 0.019887 mol CaCO3 1 100.09g 2.Calculate the hoagie mass of the nameless carbonate. don this value in the data Table. Mass of M2CO3 / mol CaCO3 1.851g / 0.019887 mol = 93.08 g/mol M2CO3 3.From the measured molar, identify the unmapped. Calculate the percent error in the molar mass value. Enter both values in the entropy Table. Molar Mass Na2CO3 = 105.99 g/mol this is the closest molar mass to what I calculated, so the unknown M2CO3 must be sodium carbonate. Percent Error: 93.08g/mol 105.99 g/mol (100) = 12.18% error 105.

99 g/mol DISCUSSION crumple the procedure and list the possible sources of error that would cause all(prenominal) the molar mass of the unknown to be (a) too laid-back or (b) too low. The goal of this lab was to discover the unknown classify 1 metal (M) of the compound M2CO3 by miscellanea state the compound in water and adding a termination of calcium chloride, CaCl 2 to the solution in order to precipitate th! e carbonate ions to describe the molar mass of the unknown element, thus find out the individualism of the unknown element. The initial hypothesis was that the metal carbonate would be potassium carbonate, or K2CO3, because potassium is a group 1 element that is very similar to calcium, but in that respect argon many other group 1 elements that could draw ensure that mold. After filtering the precipitate, it was discovered that the molar mass of...If you indirect request to outsmart a full essay, order it on our website: BestEssayCheap.com

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